16v+12v^2=4v(4+a)

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Solution for 16v+12v^2=4v(4+a) equation:


Simplifying
16v + 12v2 = 4v(4 + a)
16v + 12v2 = (4 * 4v + a * 4v)

Reorder the terms:
16v + 12v2 = (4av + 16v)
16v + 12v2 = (4av + 16v)

Add '-16v' to each side of the equation.
16v + -16v + 12v2 = 4av + 16v + -16v

Combine like terms: 16v + -16v = 0
0 + 12v2 = 4av + 16v + -16v
12v2 = 4av + 16v + -16v

Combine like terms: 16v + -16v = 0
12v2 = 4av + 0
12v2 = 4av

Solving
12v2 = 4av

Solving for variable 'v'.

Reorder the terms:
-4av + 12v2 = 4av + -4av

Combine like terms: 4av + -4av = 0
-4av + 12v2 = 0

Factor out the Greatest Common Factor (GCF), '4v'.
4v(-1a + 3v) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'v' equal to zero and attempt to solve: Simplifying v = 0 Solving v = 0 Move all terms containing v to the left, all other terms to the right. Simplifying v = 0

Subproblem 2

Set the factor '(-1a + 3v)' equal to zero and attempt to solve: Simplifying -1a + 3v = 0 Solving -1a + 3v = 0 Move all terms containing v to the left, all other terms to the right. Add 'a' to each side of the equation. -1a + a + 3v = 0 + a Combine like terms: -1a + a = 0 0 + 3v = 0 + a 3v = 0 + a Remove the zero: 3v = a Divide each side by '3'. v = 0.3333333333a Simplifying v = 0.3333333333a

Solution

v = {0, 0.3333333333a}

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